15x^2+-14=-8

Solution for 15x^2+-14=-8 equation:

15x^2+-14=-8

We move all terms to the left:

15x^2+-14-(-8)=0

We add all the numbers together, and all the variables

15x^2-6=0

a = 15; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·15·(-6)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{10}}{2*15}=\frac{0-6\sqrt{10}}{30}
=-\frac{6\sqrt{10}}{30}
=-\frac{\sqrt{10}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{10}}{2*15}=\frac{0+6\sqrt{10}}{30}
=\frac{6\sqrt{10}}{30}
=\frac{\sqrt{10}}{5}
$